3x^2+100x+35000=231800

Solution for 3x^2+100x+35000=231800 equation:

3x^2+100x+35000=231800

We move all terms to the left:

3x^2+100x+35000-(231800)=0

We add all the numbers together, and all the variables

3x^2+100x-196800=0

a = 3; b = 100; c = -196800;
Δ = b2-4ac
Δ = 1002-4·3·(-196800)
Δ = 2371600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2371600}=1540$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-1540}{2*3}=\frac{-1640}{6}
=-273+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+1540}{2*3}=\frac{1440}{6}
=240
$